为什么这个示例脚本会在令牌附近输出错误？(Why do this sample script, keep outputting error near token?)

 在这里输入图像描述我试图看看shell脚本是如何工作的以及如何运行它们，所以我从一本名为“Wicked Cool Shell Scripts”的图书库中找到的一本书中提取了一些示例代码。 
 
 我逐字写了代码，但是我从Linux得到了一个错误，我在编译代码时说： 
 
 
 
 'd.sh：第3行：意外令牌附近的语法错误`{ 
 
 
 'd.sh：第3行：`gmk（）{ 
 
 
 在此之前，我在换行符上有大括号，但我仍然得到： 
 
 
 
 'd.sh：第3行：意外令牌附近的语法错误 
 
 
 'd.sh：第3行：`gmk（） 
 
 
#!/bin/sh
#format directory- outputs a formatted directory listing 
gmk()
 {
#Give input in Kb, output converted to Kb, Mb, or Gb for best output format
    if [$1 -ge 1000000]; then
        echo "$(scriptbc -p 2 $1/1000000)Gb"
    elif [$1 - ge 1000]; then
        echo "$$(scriptbc -p 2 $1/1000)Mb"
    else
        echo "${1}Kb"
        fi
}

    if [$# -gt 1] ; then 
        echo "Usage: $0 [dirname]" >&2; exit 1
    elif [$# -eq 1] ; then 
        cd "$@"
        fi

    for file in *

    do 
        if [-d "$file"] ; then
            size = $(ls "$file"|wc -l|sed 's/[^[:digit:]]//g')
        elif [$size -eq 1] ; then
            echo "$file ($size entry)|"
        else
            echo "$file ($size entries)|"
    fi
        else
            size ="$(ls -sk "$file" | awk '{print $1}')"
            echo "$file ($(gmk $size))|"
    fi
    done | \
      sed 's/ /^^^/g' |\
      xargs -n 2 |\
      sed 's/\^\^\^/ /g' | \
      awk -F\| '{ printf "%39s %-39s\n", $1, $2}'
      exit 0

    if [$#-gt 1]; then 
        echo "Usage :$0 [dirname]" >&2; exit 1
    elif [$# -eq 1]; then 
        cd "$@"
    fi

    for file in *
        do
            if [ -d "$file" ] ; then
                size =$(ls "$file" | wc -l | sed 's/[^[:digit:]]//g')
            if [ $size -eq 1 ] ; then
                echo "$file ($size entry)|"
            else
                echo "$file ($size entries)|"
                fi
            else
                size ="$(ls -sk "$file" | awk '{print $1}')"
                echo "$file ($(convert $size))|"
                fi
done | \
    sed 's/ /^^^/g' | \
    xargs -n 2 | \
    sed 's/\^\^\^/ /g' | \
    awk -F\| '{ printf "%-39s %-39s\n", $1, $2 }'

    exit 0
 

enter image description hereI was trying to see how a shell scripts work and how to run them, so I toke some sample code from a book I picked up from the library called "Wicked Cool Shell Scripts"
 
I re wrote the code verbatim, but I'm getting an error from Linux, which I compiled the code on saying:
 
 
 
'd.sh: line 3: syntax error near unexpected token `{ 
 
 
'd.sh: line 3:`gmk() {
 
 
Before this I had the curly bracket on the newline but I was still getting :
 
 
 
'd.sh: line 3: syntax error near unexpected token 
 
 
'd.sh: line 3:`gmk()
 
 
#!/bin/sh
#format directory- outputs a formatted directory listing 
gmk()
 {
#Give input in Kb, output converted to Kb, Mb, or Gb for best output format
    if [$1 -ge 1000000]; then
        echo "$(scriptbc -p 2 $1/1000000)Gb"
    elif [$1 - ge 1000]; then
        echo "$$(scriptbc -p 2 $1/1000)Mb"
    else
        echo "${1}Kb"
        fi
}

    if [$# -gt 1] ; then 
        echo "Usage: $0 [dirname]" >&2; exit 1
    elif [$# -eq 1] ; then 
        cd "$@"
        fi

    for file in *

    do 
        if [-d "$file"] ; then
            size = $(ls "$file"|wc -l|sed 's/[^[:digit:]]//g')
        elif [$size -eq 1] ; then
            echo "$file ($size entry)|"
        else
            echo "$file ($size entries)|"
    fi
        else
            size ="$(ls -sk "$file" | awk '{print $1}')"
            echo "$file ($(gmk $size))|"
    fi
    done | \
      sed 's/ /^^^/g' |\
      xargs -n 2 |\
      sed 's/\^\^\^/ /g' | \
      awk -F\| '{ printf "%39s %-39s\n", $1, $2}'
      exit 0

    if [$#-gt 1]; then 
        echo "Usage :$0 [dirname]" >&2; exit 1
    elif [$# -eq 1]; then 
        cd "$@"
    fi

    for file in *
        do
            if [ -d "$file" ] ; then
                size =$(ls "$file" | wc -l | sed 's/[^[:digit:]]//g')
            if [ $size -eq 1 ] ; then
                echo "$file ($size entry)|"
            else
                echo "$file ($size entries)|"
                fi
            else
                size ="$(ls -sk "$file" | awk '{print $1}')"
                echo "$file ($(convert $size))|"
                fi
done | \
    sed 's/ /^^^/g' | \
    xargs -n 2 | \
    sed 's/\^\^\^/ /g' | \
    awk -F\| '{ printf "%-39s %-39s\n", $1, $2 }'

    exit 0
 

原文：https://stackoverflow.com/questions/18051283