函数调用可以重新排序(Can function calls be reordered)

 我正在使用C ++ 98。 函数调用可以在多大程度上被重新排序？ 我没有使用任何全局状态，只有函数本地的对象状态。 
 
 我的具体情况是： 
 
{
  RaiiType T;
  Object1.FunctionCall();
  Object2.FunctionCall();
}
 
 Object1和Object2在下一个范围内声明。 T的构造函数是否允许在两个函数调用之后重新排序，假设它可以被平凡地证明（至少对于人类而言）在构造函数调用和函数调用之间没有依赖关系？ 
 
 
 在我的特殊情况下，RAII对象用于定时执行函数调用。 

I am using C++98. To what extent can function calls be reordered? I am not using any global state, only state of objects local to the function.
 
My particular case is:
 
{
  RaiiType T;
  Object1.FunctionCall();
  Object2.FunctionCall();
}
 
Where Object1 and Object2 are declared in the next scope up. Is the constructor for T permitted to be reordered after either function call, assuming that it can be trivially proven (at least to a human) that there are no dependencies between the construction and the function calls?
 
 
In my particular case, the RAII object is used to time the execution of the function calls.

原文：https://stackoverflow.com/questions/30606924