首页 \ 问答 \ jquery ajax循环只返回最后一个值(jquery ajax loop only returning last value)

jquery ajax循环只返回最后一个值(jquery ajax loop only returning last value)

我有几个不同服务的ajax调用。 我知道每次连续调用都会覆盖我的数组var log ,但我无法弄清楚如何更改逻辑以附加下一个数组而不是覆盖。

$.ajax($.extend({}, ajaxDefaults, source, {
                data: data,
                success: function(events) {
                    events = events || [];
                    var res = applyAll(success, this, arguments);
                    if ($.isArray(res)) {
                        events = res;
                    }
                    callback(events);


                  var log = log || [];
                      for (var i=0; i<events.length; i++) {
                        log.push(events[i]);
                    }
                    console.log(log);

                },
                error: function() {
                    applyAll(error, this, arguments);
                    callback();
                },
                complete: function(events) {
                    applyAll(complete, this, arguments);
                    popLoading();

                }
            }));

I have an ajax call to several different services. I know my array var log is being overwritten by each successive call, but I can't figure out how to change the logic to append the next array instead of overwriting.

$.ajax($.extend({}, ajaxDefaults, source, {
                data: data,
                success: function(events) {
                    events = events || [];
                    var res = applyAll(success, this, arguments);
                    if ($.isArray(res)) {
                        events = res;
                    }
                    callback(events);


                  var log = log || [];
                      for (var i=0; i<events.length; i++) {
                        log.push(events[i]);
                    }
                    console.log(log);

                },
                error: function() {
                    applyAll(error, this, arguments);
                    callback();
                },
                complete: function(events) {
                    applyAll(complete, this, arguments);
                    popLoading();

                }
            }));

原文:https://stackoverflow.com/questions/29908972
更新时间:2024-05-04 16:05

最满意答案

我最近有同样的问题。 但是有一点延迟(超时)为我解决了这个问题:

jQuery(document).ready(function($){
    window.setTimeout(function(){
        $('input.datepicker').Zebra_DatePicker();
    }, 100);
});

I recently have the same problem. But a little delay (timeout) solves the issue for me:

jQuery(document).ready(function($){
    window.setTimeout(function(){
        $('input.datepicker').Zebra_DatePicker();
    }, 100);
});

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