首页
\
问答
\
BackPack PageManager fields.select_page_template未找到(BackPack PageManager fields.select_page_template not found)
BackPack PageManager fields.select_page_template未找到(BackPack PageManager fields.select_page_template not found)
访问页面或创建页面时出现以下错误:
ErrorException in FileViewFinder.php line 137: View [fields.select_page_template] not found. (View: /home/ubuntu/pbc/vendor/backpack/crud/src/resources/views/inc/show_fields.blade.php) (View: /home/ubuntu/pbc/vendor/backpack/crud/src/resources/views/inc/show_fields.blade.php) (View: /home/ubuntu/pbc/vendor/backpack/crud/src/resources/views/inc/show_fields.blade.php)
遵循此解决方案: 尝试从供应商中删除您的背包文件夹并再次进行作曲家更新
While accessing pages or creating pages getting the following error:
ErrorException in FileViewFinder.php line 137: View [fields.select_page_template] not found. (View: /home/ubuntu/pbc/vendor/backpack/crud/src/resources/views/inc/show_fields.blade.php) (View: /home/ubuntu/pbc/vendor/backpack/crud/src/resources/views/inc/show_fields.blade.php) (View: /home/ubuntu/pbc/vendor/backpack/crud/src/resources/views/inc/show_fields.blade.php)
Followed this solution: Try to remove your backpack folder from the vendor and do the composer update again
原文:https://stackoverflow.com/questions/42725816
更新时间:2022-09-14 07:09
最满意答案
尝试使用
Exists
考虑到您的独特组合是
PSTL_CODE
和phone
SELECT * FROM sheet1 a WHERE EXISTS (SELECT 1 FROM sheet1 b WHERE a.pstl_code = b.pstl_code AND a.phone = b.phone HAVING Count(*) = 1) ORDER BY phone
最好在
PSTL_CODE
和phone
列上定义Unique Constraint
,以帮助您避免表中的重复记录Try using
Exists
Considering that your unique combination is
PSTL_CODE
andphone
SELECT * FROM sheet1 a WHERE EXISTS (SELECT 1 FROM sheet1 b WHERE a.pstl_code = b.pstl_code AND a.phone = b.phone HAVING Count(*) = 1) ORDER BY phone
It is better to define a
Unique Constraint
onPSTL_CODE
andphone
columns which helps you to avoid duplicate records in table
相关问答
更多-
如果第2列和第3列匹配使用awk,如何删除重复的行?(How to delete repeated rows if column 2 and column 3 matches using awk?)[2023-02-10]
awk '{a[NR]=$2""$3} a[NR]!=a[NR-1]{print}' file 将$2和$3值保存到索引为NR数组a 。 然后,如果当前行和前一行中的值与打印行不匹配,则忽略。 awk '{a[NR]=$2""$3} a[NR]!=a[NR-1]{print}' file Save $2 and $3 value to array a with index as NR. Then if value of a in current line and previous line doesn' ... -
好吧,我将借助于对给定字符串中的字符进行排序的函数来完成此操作。 所以首先让我们创建一个函数 create or replace function sortString(str in Varchar2) return varchar2 is res varchar2(500); begin SELECT MIN(permutations) into res FROM (SELECT REPLACE (SYS_CONNECT_BY_PATH (n, ','), ',') permutations ...
-
如果您想要的是具有ColB-ColC组合的第一行,则以下将执行此操作: select min(id) as id, colB, colC from tbl group by colB, colC order by id SQL小提琴 If all you want is the first row with a ColB-ColC combination, the following will do it: select min(id) as id, colB, colC from tbl group b ...
-
我已经为你看过了。 在第一个示例中,集合将仅包含唯一项。 您可以遍历集合以访问它们。 在第二个例子中,我使用字典 - 您可以更轻松地获得独特的项目。 这个给你: Sub arr_parse_test() Dim rra As Variant Dim i As Integer Dim Dict As New Collection rra = Array("a", "b", "c", "d", "g", "a", "b", "z") On Error Resume Next For i = 0 To U ...
-
从R中的data.frame中删除每个间隔的重复行(Removing repeated rows with each interval from data.frame in R)[2022-09-07]
以下代码使您感兴趣的三列成为单个向量。 然后,我只测试向量之间的相等性,它的偏移量为1.当这是假的时,你已经转换到一个新的XYZ项目。 n <- nrow(ss) xyz <- with(ss, paste0(X, Y, Z)) sel <- xyz[1:(n-1)] != xyz[2:n] ss[c(TRUE,sel),] #the first one would always be true 这比朱利叶斯回答快约3倍。 随着数据集的增长,优势应该会变得更大。 The following code m ... -
查找和删除SQL Server行中的重复列值(Finding and removing duplicate column values in a SQL Server row)[2023-12-05]
Sql在这里小提琴 。 update PhoneNumbers set Tel2 = case when Tel1 = Tel2 then null else Tel2 end, Tel3 = case when Tel3 in (Tel1, Tel2) then null else Tel3 end, Tel4 = ... -
您只需 awk '$NF != prev {print} {prev=$NF}' 编辑:处理新的输入 awk '{ if (NF == 1) value = $1 else { key = $1 SUBSEP $2 SUBSEP $3 value = $4 } if ((key SUBSEP value) in val) next print val[key, value] = 1 }' ...
-
SELECT t.lr_no, t.seq, t.len FROM YourTable t INNER JOIN (SELECT lr_no, MAX(len) AS MaxLen FROM YourTable GROUP BY lr_no) q ON t.lr_no = q.lr_no AND t.len = q.MaxLen S ...
-
尝试使用Exists 考虑到您的独特组合是PSTL_CODE和phone SELECT * FROM sheet1 a WHERE EXISTS (SELECT 1 FROM sheet1 b WHERE a.pstl_code = b.pstl_code AND a.phone = b.phone HAVING Count(*) = 1) ORDE ...
-
使用从第二个字段到结尾的选定键sort ( -k2 ): sort -t '\t' -uk2 file.txt -t '\t'将字段分隔符设置为Tab -u根据所选键获取唯一条目 例: % sort -uk2 file.txt Gen6 0.4353 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 Gen1 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 Gen3 1.0 1.0 1.0 5.0 0.55 1.0 1.0 1.0 1.0 sort with sel ...